Finding the duplicate element and the missing element in the given list with o(n) time complexity.

POULAMI BAKSHI
Apr 21, 2021

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Question to solve!!

This article describes the implementation of the program to find the duplicate number in a given list of numbers using the minimum time complexity.

Code!!

Step 1:

we take input some numbers that contain duplicate numbers.

Step 2:

we create a new list which is having the same length as the first list. But, contains till n numbers.

Step 3:

we find the sum of the given array and the actual array. Now, find the difference between the sum of the array.

Step 4:

we find the sum of the square of the given array and the actual array. Now, find the difference between the sum of the square of the array.

Step 5:

Finally, we found the repeated and the missing element.

Thank you!!..

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